Question
A cube whose volume is $\frac{1}{8}$ cubic centimeter is placed on top of a cube whose volume is $1\ cm^3.$ The two cubes are then placed on top of a third cube whose volume is $8\ cm^3.$ The height of the stacked cubes is:

Answer

Let $a, b, c.$ be the sides of three cubes
Then $a^3 =\frac{1}{8}$
$\Rightarrow\text{a}=\frac{1}{2}$
$b^3= 1 $
$\Rightarrow b = 1$
$c^3 = 8 $
$\Rightarrow c = 2,$
Now height of resulting cube
$0.5 + 1 + 2 $
$= 3.5\ cm$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

In a quadrilateral $\text{ABCD,}$ it is given that $BD = 16\ cm$. If $\text{AL}\perp\text{BD}$ and $\text{CM}\perp\text{BD}$ such that $AL = 9\ cm$ and $CM = 7\ cm,$ then $ar($quadrilateral $\text{ABCD}) =$ ?
In a histogram the area of each rectangle is proportional to:
  1. The class mark of the corresponding class interval.
  2. The class size of the corresponding class interval.
  3. Frequency of the corresponding class interval.
  4. Cumulative frequency of the corresponding class interval.
A cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius. The number of balls will be
  1. 4
  2. 3
  3. 6
  4. 8
If h, S and V denote respectively  the height, curved surface area and volume of a right circular cone, then $3\pi\text{V}\text{h}^3-\text{S}^2\text{h}^2+\text{9V}^2$ is equal to:
  1. $8$
  2. $0$
  3. $4\pi$
  4. $32\pi^2$
The value of $\Big(\frac{256\text{x}^{16}}{81\text{y}^4}\Big)^{-\frac{1}{4}}$ is:
  1. $\frac{3\text{y}}{8\text{x}^4}$
  2. $\frac{3\text{y}}{4\text{x}^4}$
  3. $\frac{4\text{y}}{5\text{x}^4}$
  4. $\frac{4\text{x}^4}{3\text{y}}$
The seventh root of x divided by the eighth root of x is:
If a, b, c are the lengths of the sides of a triangle, then