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In the diagram, $I_1$ , $I_2$ are the strength of the currents in the loop and infinite long straight conductor respectively. $OA = AB = R$ . The net magnetic field at the centre $O$ is zero. Then the ratio of the currents in the loop and the straight conductor is
Statement $-1$ : Path of the charge particle may be straight line in uniform magnetic field. Statement $-2$ : Path of the charge particle is decided by the angle between its velocity and the magnetic force working on it
A proton and an alpha particle both enter a region of uniform magnetic field $B,$ moving at right angles to the field $B.$ If the radius of circular orbits for both the particles is equal and the kinetic energy acquired by proton is $1\,\, MeV,$ the energy acquired by the alpha particle will be......$MeV$
The electron in the beam of a television tube move horizontally from south to north. The vertical component of the earth's magnetic field points down. The electron is deflected towards
A very long conducting wire is bent in a semicircular shape from $A$ to $B$ as shown in figure. The magnetic field at point $P$ for steady current configuration is given by:
A wire carrying a current $I$ is placed inside a uniform magnetic field $\vec B=-B_0\hat k$. The shape of the wire is parabolic and has equation $Y = 2x -x^2.$ The force on the wire will be :