A current of $1.6\, A$ is flowing through a wire having cross-sectional area $1\, mm^2$. If density of free electrons in the material of the wire is $10^{29}\, per\, m^3$, the drift velocity of electrons will be
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$\mathrm{i}=\mathrm{neA} \mathrm{\,Vd}$
$\mathrm{V}_{\mathrm{d}}=\frac{\mathrm{i}}{\mathrm{neA}}=\frac{1.6}{10^{29} \times 1.6 \times 10^{-19}} \times\left(10^{-3}\right)^{2}$
$=\frac{1}{10^{10} \times 10^{-6}}=10^{-4} \mathrm{\,m} / \mathrm{sec}$
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