MCQ
A current of strength $2.5$ amp was passed through $CuS{O_4}$ solution for $6$  minutes $26$ seconds. The amount of copper deposited is .............. $\mathrm{g}$ (Atomic weight of $Cu = 63.5$) ($1$ faraday $=\,96500$ coulombs)
  • $0.3175$
  • B
    $3.175$
  • C
    $0.635$
  • D
    $6.35$

Answer

Correct option: A.
$0.3175$
a
(a) $Q = 2.5 \times 386 = 96500\,C$

$2\,F(2 \times 96500\,C)$ deposited $Cu = 63.5\,g$

Hence $965\,C$  will deposited; $Cu = 0.3175\,gm$.

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