MCQ
A cyclic process $ABCA$ is shown in $PT$ diagram. When presented on $PV$, it would


- A

- B

- ✓

- D







From $C$ to $A, P \propto T$
Hence, the volume is constant.
From $B$ to $C$, the temperature is constant.
Hence, $P \propto \frac{1}{V}$
From $C$ to $A,$ volume is constant.
Hence, when presented on $P V,$ it would be represented by option $\mathrm{C}$.
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Reason : The binding energy of ${}^{35}Cl$ is too small.