Question
A dice is thrown once. What is the probability that the number is greater than 2?
✓
Answer
Event = {number is greater than 2}
Event = {3, 4, 5, 6}
n(E) = 4
P(E) = ?
P(E) = $\frac{ n ( E )}{ n ( S )}=\frac{4}{6}=\frac{2}{3}$.
Event = {3, 4, 5, 6}
n(E) = 4
P(E) = ?
P(E) = $\frac{ n ( E )}{ n ( S )}=\frac{4}{6}=\frac{2}{3}$.
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