Question
A die is thrown, find the probability of getting:a prime number

Answer

A die has six numbers: $1,2,3,4,5,6$
$\therefore$ Number of possible outcomes $=6$
a prime number
Numbers of favourable outcomes $=$ a prime
number $=1,3,5$ which are $3$ in numbers
$P(E)=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$
$=\frac{3}{6}=\frac{1}{2}$

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