A dielectric slab of thickness d is inserted in a parallel plate … - Vidyadip

MCQ

A dielectric slab of thickness $d$ is inserted in a parallel plate capacitor whose negative plate is at $x = 0$ and positive plate is at $x = 3d$. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from $0$ to $3d$

A
The magnitude of the electric field remains the same
B
The direction of the electric field remains the same
C
The electric potential increases continuously
✓
Both $(b)$ and $(c)$

✓

Answer

Correct option: D.

Both $(b)$ and $(c)$

d
(d) Even after introduction of dielectric slab, direction of electric field will be perpendicular to the plates and directed from positive plate to negative plate.
Further, magnitude of electric field in air $ = \frac{\sigma }{{{\varepsilon _0}}}$
Magnitude of electric field in dielectric $ = \frac{\sigma }{{K{\varepsilon _0}}}$
Similarly electric lines always flows from higher to lower potential, therefore, electric potential increases continuously as we move from $x = 0$ to $x = 3d$.

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