Question
A disc of mass $4 \mathrm{~kg}$ rolls on a horizontal surface. If its linear speed is $3 \mathrm{~m} / \mathrm{s}$, what is its total kinetic energy?

Answer

Total kinetic energy of the disc
$
=\frac{3}{4} \mathrm{Mv}^2=\frac{3}{4} \times 4 \times(3)^2=27 \mathrm{~J}
$

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