MCQ
A faulty thermometer has its fixed points marked $5^o$ and $95^o$. This thermometer reads the temperature of a body as $59^o$. Then the correct temperature of the body on celsius scale is ........ $^o$
- A$59$
- B$58$
- ✓$60$
- D$61$
$\frac{T_{C}-0}{100}=\frac{x \text { -lower fixed point }}{\text { upper fixed point - lower fixxed point }}$
$\frac{T_{C}}{100}=\frac{59-5}{95-5}=\frac{540}{90}=\frac{3}{5}$
$T_{C}=\frac{3000}{5}=60^{\circ}$
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