$\therefore \quad \mathrm{T}=\frac{\mathrm{W}}{2 \sin \theta}$
Also, $\mathrm{T} \cos \theta=\mathrm{T}_{0}$
$\therefore \quad \mathrm{T}_{0}=\mathrm{T} \cos \theta$
$\mathrm{T}_{0}=\frac{\mathrm{W}}{2 \sin \theta} \cos \theta$
$=\frac{W}{2} \cot \theta$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List-$I$ | List-$II$ |
| $P$ $\dot{r}(t)=\alpha t \hat{t}+\beta t \hat{j}$ | $1$ $\overrightarrow{ p }$ |
| $Q$ $\dot{r}(t)=\alpha \cos \omega t \hat{i}+\beta \sin \omega t \hat{j}$ | $2$ $\overrightarrow{ L }$ |
| $R$ $\dot{r}(t)=\alpha(\cos \omega t \hat{i}+\sin \omega t \hat{j})$ | $3$ $K$ |
| $S$ $\dot{r}(t)=\alpha t \hat{i}+\frac{\beta}{2} t^2 \hat{j}$ | $4$ $U$ |
| $5$ $E$ |