Question
A flooring tile has the shape of a parallelogram whose base is $24\ cm$ and the corresponding height is $10\ cm.$ How many such tiles are required to cover a floor of area $1080\ m^2$?
✓
Answer
Area of floor $=1080\ m^2$
Base of parallelogram shaped tile $(b) =24\ cm$
and corresponding height $(h)=10\ cm$
Area of one tile $= b \times h =24 \times 10=240\ cm^2$ $=\frac{240}{10000}=\frac{24}{100} m^2$
$\therefore$ Number of tiles required $=\frac{\frac{1080}{24}}{1000}$
$=2080 \times \frac{1000}{0}=45000$
Base of parallelogram shaped tile $(b) =24\ cm$
and corresponding height $(h)=10\ cm$
Area of one tile $= b \times h =24 \times 10=240\ cm^2$ $=\frac{240}{10000}=\frac{24}{100} m^2$
$\therefore$ Number of tiles required $=\frac{\frac{1080}{24}}{1000}$
$=2080 \times \frac{1000}{0}=45000$
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