MCQ
A force $\vec F = 3\hat i + c\hat j + 2\hat k$ acting on a particle causes a displacement $\vec S = - 4\hat i + 2\hat j - 3\hat k$ in its own direction. If the work done is $6J$, then the value of $c$ will be
- ✓$12$
- B$6$
- C$1$
- D$0$
✓
Answer
Correct option: A.
$12$
a
(a) $W = \overrightarrow F .\overrightarrow s = (3\hat i + c\hat j + 2\hat k).( - 4\hat i + 2\hat j - 3\hat k)$$ = - 12 + 2c - 6$
(a) $W = \overrightarrow F .\overrightarrow s = (3\hat i + c\hat j + 2\hat k).( - 4\hat i + 2\hat j - 3\hat k)$$ = - 12 + 2c - 6$
Work done $ = 6J$ (given)
$\therefore $ $ - 12 + 2c - 6 = 6$$ \Rightarrow $ $c = 12$
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