MCQ
A four $-$ digit number is formed by using the digits $1, 2, 4, 8$ and $9$ without repitition. If one number is selected from those numbers, then what is the probability that it will be an odd number?
  • A
    $\frac{1}{5}$
  • $\frac{2}{5}$
  • C
    $\frac{3}{5}$
  • D
    $\frac{4}{5}$

Answer

Correct option: B.
$\frac{2}{5}$
Total number of outcomes $= 5 \times 4 \times 3 \times 2 = 120$
he number of favourable cases $= 2 (4 \times 3 \times 2) - = 48 \ ($i.e., odd numbers$)$
herefore,Required probability $=\frac{48}{120}=\frac{2}{5}.$

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