MCQ
A four$-$digit number is formed by using the digits $1, 2, 4, 8$ and $9$ without repitition. If one number is selected from those numbers, then what is the probability that it will be an odd number?
  • A
    $\frac15$
  • $\frac25$
  • C
    $\frac35$
  • D
    $\frac45$

Answer

Correct option: B.
$\frac25$
Total number of outcomes $= 5 \times 4 \times 3 \times 2 = 120$
The number of favourable cases $= 2(4 \times 3 \times 2) = 48 ($i.e., odd numbers$)$
Therefore,
Required probability $\frac{48}{120}=\frac25$

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