MCQ
A frictionless pulley is attached to one arm of a balance and a string passed around it carries two masses $m_1$ and $m_2$. The pulley is provided with $a$ clamp due to which $m_1$ and $m_2$ do not move $w.r.t.$ each other.  On removing the clamp, $m_1$ and $m_2$ start moving. How much change in counter mass has to be made to restore balance? 
  • A
    $\frac{{{{({m_1} + {m_2})}^2}}}{{{m_1} - {m_2}}}$
  • $\frac{{{{({m_1} - {m_2})}^2}}}{{{m_1} + {m_2}}}$
  • C
    $2m_1 -m_2$
  • D
    $m_1 -m_2$

Answer

Correct option: B.
$\frac{{{{({m_1} - {m_2})}^2}}}{{{m_1} + {m_2}}}$
b
When the clamp is removed, the pull on the left arm (i.e., tension) $=$ $\frac {4 \mathrm{m}_{1} \mathrm{m}_{2} \mathrm{g}} {\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)}$

When the clamp is not removed, the tension

$=\left(m_{1}+m_{2}\right) g$

$\mathrm{W}=$ Increase in counter weight

$=\frac{4 m_{1} m_{2} g}{\left(m_{1}+m_{2}\right)}-\left(m_{1}+m_{2}\right) g=-\frac{\left(m_{1}-m_{2}\right)^{2}}{\left(m_{1}+m_{2}\right)} g$

Decrease in counter weight $=\frac{\left(m_{1}-m_{2}\right)^{2} g}{\left(m_{1}+m_{2}\right)}$

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