MCQ
A fully charged capacitor has a capacitance $‘C’$. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $‘s’$ and mass $‘m’$. If the temperature of the block is raised by ‘$\Delta T$’, the potential difference $‘V’$ across the capacitance is
  • A
    $\frac{{ms\Delta T}}{C}$
  • $\sqrt {\frac{{2ms\Delta T}}{C}} $
  • C
    $\sqrt {\frac{{2mC\Delta T}}{s}} $
  • D
    $\frac{{mC\Delta T}}{s}$

Answer

Correct option: B.
$\sqrt {\frac{{2ms\Delta T}}{C}} $
b
(b) $\frac{1}{2}C{V^2} = m.s.\Delta T$ $==>$ $V = \sqrt {\frac{{2ms\Delta T}}{C}} $

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