A galvanometer having a coil resistance of $60\,\Omega $ shows full scale deflection when a current of $1.0\, amp$ passes through it. It can be converted into an ammeter to read currents upto $5.0\, amp$ by
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$\mathrm{I}_{\mathrm{g}} \cdot \mathrm{G}=\left(\mathrm{I}-\mathrm{I}_{\mathrm{g}}\right) \cdot S$
$\therefore S=\frac{I_{g} \cdot G}{\left(I-I_{g}\right)}$
Given $\mathrm{I}=5 \mathrm{\,A}, \mathrm{I}_{\mathrm{g}}=1 \mathrm{\,Amp} ., \mathrm{G}=60 \mathrm{\,M}$
$\therefore \quad S=\frac{60 \times 1}{4}=15\, \Omega$ in parallel
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