A galvanometer of resistance $100\,\Omega $ has $50\, divisions$ on its scale and has sensitivity of $20\,\mu A / division$. It is to be converted to a voltmeter with three ranges, of $0-2\, V$, $0-10\, V$ and $0-20\, V$. The appropriate circuit to do so is
A
B
C
D
JEE MAIN 2019, Diffcult
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C
c $20 \times 50 \times 10^{-6}=10^{-3}\, \mathrm{Amp}$
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