A galvanometer whose resistance is $120\,\Omega $ gives full scale deflection with a current of $0.05\, A$ so that it can read a maximum current of $10\, A$. A shunt resistance is added in parallel with it. The resistance of the ammeter so formed is .............. $\Omega $
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(c) Resistance of shunted ammeter$ = \frac{{GS}}{{G + S}}$
Also $\frac{i}{{{i_g}}} = 1 + \frac{G}{S}$
$ \Rightarrow $ $\frac{{GS}}{{G + S}} = \frac{{{i_g}.G}}{i}$
$ \Rightarrow $ $\frac{{GS}}{{G + S}} = \frac{{0.05 \times 120}}{{10}}$= $0.6 \,\Omega$
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