- ✓$tan^{-1}(3)$
- B$tan^{-1}(1/3)$
- C$cos^{^{-1}}(3)$
- D$sin^{-1}(1/3)$
$\mathrm{V}_{\mathrm{car}}=2 \hat{\mathrm{i}}$
$V_{\text {drops }}=6 \hat{j}$
$\mathrm{V}_{\text {drops }} \mathrm{W} .$ $r.t$ car $=\mathrm{V}_{\text {drops }}-\mathrm{V}_{\text {car }}$
$=-2 \hat{i}+6 \hat{j}$
$\cos \theta_{1}=\frac{\hat{j} \cdot(-2 \hat{i}+6 \hat{j})}{|\hat{j}| \cdot|-2 \hat{i}+6 \hat{j}|}$
$=\frac{6}{\sqrt{2^{2}+6^{2}} \cdot 1}=\frac{6}{\sqrt{40}}$
$\Rightarrow \cos \theta_{1}=\frac{3}{\sqrt{10}}$
$\Rightarrow \sin \theta_{2}=\frac{3}{\sqrt{10}}$
$\Rightarrow \tan \theta_{2}=3$
$\Rightarrow \theta_{2}=\tan ^{-1} 3$
Hence wind stream is inclined at tan $^{-1} 3^{\circ}$ with vertical.
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