A hammer of mass 1kg moving with a speed of 6ms^ -1 strikes a wal… - Vidyadip

Question

A hammer of mass $1kg$ moving with a speed of $6ms^{-1}$ strikes a wall and comes to rest in $0.1s$. Calculate:

The impulse of force.
The retardation of the hammer.
The retarding force that stops the hammer.

✓

Answer

Mass of the hammer $m = 1kg$ Initial velocity, $u = 6ms^{-1}$, final velocity, $v = 0$ and $t = 0.1s$

Impulse = Ft = m(v - u)

= 1(0 - 6) = -6Ns

Retarding force that stops the hammer,

$\text{F}=\frac{\text{Impulse}}{\text{time}}=\frac{6}{0.1}=60\text{N}$

Retardation of the hammer

$=\frac{\text{F}}{\text{m}}=\frac{60}{1}=60\text{ ms}^{-2}$

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