Question
A heavy nucleus breaks into comparatively lighter nuclei, which are more stable compared to the original heavy nucleus. When a heavy nucleus like uranium is bombarded by slow moving neutrons, it splits into two parts, releasing large amount of energy. The typical fission reaction of $_{92}\text{U}^{235}$.
$_{92}\text{U}^{235}+\ _0\text{n}^1\rightarrow\ _{56}\text{Ba}^{141}+\ _{36}\text{kr}^{92}+\ 3_0\text{n}^1+\ 200\text{ MeV}$
The fission of $_{92}\text{U}^{235}$ approximately released $200 MeV$ of energy.
$_{92}\text{U}^{235}+\ _0\text{n}^1\rightarrow\ _{56}\text{Ba}^{141}+\ _{36}\text{kr}^{92}+\ 3_0\text{n}^1+\ 200\text{ MeV}$
The fission of $_{92}\text{U}^{235}$ approximately released $200 MeV$ of energy.
- If $200 MeV$ energy is released in the fission of a single nucleus of $_{92}^{235}\text{U}$, the fissions which are required to produce a power of $1kW$ is.
- $3.125 \times 10^{13}$
- $1.52 \times 10^6$
- $3.125 \times 10^{12}$
- $3.125 \times 10^{14}$
- The release in energy in nuclear fission is consistent with the fact that uranium has
- More mass per nucleon than either of the two fragments.
- More mass per nucleon as the two fragment.
- Exactly the same mass per nucleon as the two fragments.
- Less mass per nucleon than either of two fragments.
- When $_{92}\text{U}^{235}$ undergoes fission, about $0.1\%$ of the original mass is converted into energy. The energy released when $1\ kg$ of $_{92}\text{U}^{235}$ undergoes fission is.
- $9 \times 10^{11}J$
- $9 \times 10^{13}J$
- $9 \times 10^{15}J$
- $9 \times 10^{18}J$
- A nuclear fission is said to be critical when multiplication factor or $K$.
- $K = 1$
- $K > 1$
- $K < 1$
- $K = 0$
- Einstein's mass-energy conversion relation $E = mc^2$ is illustrated by.
- Nuclear fission
- $\beta-$ decay
- Rocket propulsion
- Steam engine