Taking moment about the centre of hollow sphere we will get
$\text{F}\times\text{R}=\frac{2}{3}\text{MR}^2\alpha$
$\Rightarrow\alpha=\frac{3\text{F}}{2\text{MR}}$
Again, $2\pi=\Big(\frac{1}{2}\Big)\alpha\text{t}^2$ $\Big(\text{From}\ \theta=\omega_0\text{t}+\Big(\frac{1}{2}\Big)\alpha\text{t}^2\Big)$
$\Rightarrow\text{t}^2=\frac{8\pi\text{MR}}{\text{3F}}$
$\Rightarrow\text{a}_{\text{c}}=\frac{\text{F}}{\text{m}}$
$\Rightarrow\text{X}=\Big(\frac{1}{2}\Big)\text{a}_{\text{c}}\text{t}^2=\Big(\frac{1}{2}\Big)=\frac{4\pi\text{R}}{3}$
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Atomic masses are given to be
$\text{m}(^2_1\text{H})=2.014102\text{ u}$
$\text{m}(^3_1\text{H})=3.016049\text{ u}$
$\text{m}(^{12}_6\text{C})=12.000000\text{ u}$
$\text{m}(^{20}_{10}\text{Ne})=19.992439\text{ u}$
Explain, giving reasons, whether it will behave as a converging lens or a diverging lens in each of these two media.