A horizontal overhead powerline is at height of $4\ m$ from the ground and carries a current of $100\ A$ from east to west. The magnetic field directly below it on the ground is. ${\mu _o}$$=4$$\pi $$ \times 10^{-7}$ $\frac{{Tm}}{A}$
AIEEE 2008, Medium
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The magnetic field is
$B=\frac{\mu_{0} 2 I}{4 \pi r}$
$ = \frac{{{{10}^{ - 7}} \times 2 \times 100}}{4}$
$=5 \times 10^{-6} \,T$
According to right hand palm rule, the magnetic field is directed towards south
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