MCQ
A horizontal right angle pipe bend has crosssectional area $=$ $10 $ $cm^2$ and water flows through it at speed $=$ $20$ $m/s$. The force on the pipe bend due to the turning of water is ........ $N$
- ✓$565.7$
- B$400$
- C$20$
- D$282.8$
force$=(\text {density} \times \text {area} \times \text {velocity}) \times\left(\text {velocity} \times 2^{\frac{1}{2}}\right)$
$=565.7 N$
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| Moleculae type | $\frac{C _{ P }}{ C _{ v }}$ |
| $(A)$ Monoatomic | $(I)$ $\frac{7}{ 5}$ |
| $(B)$ Diatomic rigid molecules | $(II)$ $\frac{9}{7}$ |
| $(C)$ Diatomic non-rigid molecules | $(III)$ $\frac{4}{3}$ |
| $(D)$ Triatomic rigid molecules | $(IV)$ $\frac{5}{3}$ |