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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
A hydrocarbon $A (V.D. = 36)$ forms only one monochloro substitution product. $A$ will be
  • A
    iso-pentane
  • ✓
    neo-pentane
  • C
    cyclohexane
  • D
    methyl-cyclohexane
✓

Answer

Correct option: B.
neo-pentane
b
$Mol. \,wt. = 2 \times V. D = 72$

$\therefore$ Mol. formula $= C_5H_{12}$, Structure $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,C{H_3}} \\ 
  | \\ 
  {C{H_3} - C - C{H_3}} \\ 
  | \\ 
  {\,\,\,\,\,\,\,C{H_3}} 
\end{array}$ neo-pentane

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