Question
A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.
✓
Answer
The hydrocarbon can be either a cycloalkane or an alkene since it doesn’t react with Cl2 in the dark, it can not be an alkene but must be cycloalkane since the cycloalkane reacts with Cl2 in the presence of sunlight to give a single monochloro derivative. It shows that it is cyclic hydrocarbon in which hall the hydrogen atoms are identical. Thus, it can be only cyclopentane.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Name the following halides according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:
CH3CH2CH(CH3)CH(C2H5)Cl.
CH3CH2CH(CH3)CH(C2H5)Cl.
Explain the relation between boiling point of elevation of solution ( $\Delta T _{ b }$ ) and molar mass of solute.
→Bring out the following conversion:
Acetophenone to 2-phenyl butan-2-ol.
Acetophenone to 2-phenyl butan-2-ol.
Give the equation of reaction of aniline with Benzaldehyde.
How can propan-2-one be converted into tert- butyl alcohol?
Which will be dehydrohalogenated more easily and why : $CH _3- CH _2- CH _2 Cl$ and $\left( CH _3\right)_3 Cl$ ?
→Write the formula and uses of Westron and Westrosol.
Complete synthesis by giving missing starting material, reagent or product :
Why cannot aromatic primary amines be prepared by Gabriel phthalimide synthesis ?
What type of liquids form ideal solutions?