(Take $pH_2 = 1\,atm$ ), $T = 298\,K$.
$\therefore $ $[H^+]$ changes from $1$ to $10^{-7}\,M$
Accordingly ${{E}_{red.}}=\,\frac{-\,0.059}{n}\,\log \,\frac{1}{[{{H}^{+}}]}$
$ = \,0.059\,\,\log \,{10^{ - 7}}$
i.e., $0.059\times (-7)\,=\,-0.41\,volts$
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$(1)$ $Fe^{3+}$ gives brown colour with potassium ferricyanide
$(2)$ $Fe^{2+}$ gives blue colour with potassium ferricyanide
$(3)$ $Fe^{3+}$ gives red colour with potassium thiocyanate
$(4)$ $Fe^{2+}$ gives brown colour with ammonium thiocyanate
Reason : All halogens are coloured.
Assertion $A:$ Butan$-1-$ol has higher boiling point than ethoxyethane.
Reason $R:$ Extensive hydrogen bonding leads to stronger association of molecules.
In the light of the above statements, choose the correct answer from the options given below:
