MCQ
A line passes through the point $(3, 4)$ and cuts off intercepts from the coordinates axes such that their sum is $14.$ The equation of the line is
- A$4x - 3y = 24$
- ✓$4x + 3y = 24$
- C$3x - 4y = 24$
- D$3x + 4y = 24$
Hence the equation of straight line is $\frac{x}{{14 - b}} + \frac{y}{b} = 1$.
Also, it passes through $(3,4)$
$\therefore $ $\frac{3}{{14 - b}} + \frac{4}{b} = 1 \Rightarrow b = 8$ or $7$
Therefore equations are $4x + 3y = 24$ and $x + y = 7$.
Trick : This question can be checked with the options as the line $4x + 3y = 24$ passes through $(3, 4)$ and also cuts the intercepts from the axes whose sum is $14$.
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$\mathop {Limit}\limits_{n\,\, \to \,\,\infty } $$\frac{1}{{{n^4}}}$ $\left( {\left[ {{1^3}\,x} \right]\,\, + \,\,\left[ {{2^3}\,x} \right]\,\, + \,\,......\,\, + \,\,\left[ {{n^3}\,x} \right]} \right)$ equals