Download App

11. three dimension geometry — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths11. three dimension geometry1 Mark
MCQ
A line which makes angle ${60^o}$ with $y$ - axis and $z$ - axis, then the angle which it makes with $x$ -axis is ......... $^o$
  • ✓
    $45$
  • B
    $60$
  • C
    $75$
  • D
    $30$
✓

Answer

Correct option: A.
$45$
a
(a) ${\cos ^2}\alpha = 1 - {\cos ^2}{60^o} - {\cos ^2}{60^o}$

$ = 1 - \frac{1}{4} - \frac{1}{4} = \frac{1}{2}$

==> $\alpha = {45^o}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 11. three dimension geometry→11. three dimension geometry — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If xy = ex-y then $\frac{\text{dy}}{\text{dx}}$ is:
  1. $\frac{1+\text{x}}{1+\log\text{x}}$
  2. $\frac{1-\log\text{x}}{1+\log\text{x}}$
  3. $\text{Not defined.}$
  4. $\frac{\log\text{x}}{(1+\log\text{x})^2}$
→
If $f(x) = \int {\left( {\frac{{{x^2} + {{\sin }^2}\,x}}{{1 + {x^2}}}} \right)} {\sec ^2}\,x\,dx$ and $f(0) = 0,$ then $f(1)$ equals
→
A rifleman is firing at a distant target and has only 10% chance of hiting it. the least number of round he must fire in order to have more than 50% chance of hitting it at least once is:
  1. 11
  2. 9
  3. 7
  4. 5
→
The value of $\cos ({\tan ^{ - 1}}(\tan 2))$ is
→
The feasible region is :
→
Which of the following represents coinitial vector:
  1. c, d
  2. m, b
  3. b, d
  4. Both (a) and (b)
→
The straigth line $\frac{\text{x}-3}{3}=\frac{\text{y}-2}{1}=\frac{\text{z}-1}{0}$ is:
  1. parallel to x-axis
  2. parallel to y-axis
  3. parallel to z-axis
  4. perpendicular to z-axis
→
Divide  $20$  into two parts such that the product of one part and the cube of the other is maximum. The two parts are
→
$2\cos^{-1}\text{x}=\sin^{-1}(2\text{x}\sqrt{1-\text{x}^2})$ is true for:
  1. all x
  2. x > 0
  3. $\text{x }\in[-1,1]$
  4. $\frac{1}{\sqrt{2}}\leq\text{x}\leq1$
→
A force of magnitude $ 5$ units acting along the vector  $2i - 2j + k$  displaces the point of application from $(1,\,2,\,3)$ to $(5,\,3,\,7)$, then the work done is
→