A liquid is kept in a cylindrical vessel. When the vessel is rotated about its axis, the liquid rises at its sides. If the radius of the vessel is $0.05\,\, m$ and the speed of rotation is $2$ revolutions per second, the difference in the heights of the liquid at the centre and at the sides of the vessels will be ...... $cm.$ $($ take $g = 10\,\, ms^{-2}$ and $\pi^2 = 10)$
Diffcult
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$\Delta \mathrm{h}=\frac{\omega^{2} \mathrm{R}^{2}}{2 \mathrm{g}}=\frac{(4 \pi)^{2} \times\left(\frac{1}{20}\right)^{2}}{20}=0.02 \mathrm{m}$
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