MCQ
A litre of buffer solution contains $0.1$ mole of each of $NH _3$ and $NH _4 Cl$. On the addition of $0.02\,mole$ of $HCl$ by dissolving gaseous $HCl$, the $pH$ of the solution is found to be $......\times 10^{-3}($ Nearest integer)

$\left[\right.$ Given : $pK _{ b }\left( NH _3\right)=4.745$

$\log 2=0.301$

$\log 3=0.477$

$T =298\,K ]$

  • A
    $9080$
  • $9079$
  • C
    $9081$
  • D
    $9082$

Answer

Correct option: B.
$9079$
b
In resultant solution

$n _{ NH _3}=0.1-0.02=0.08$

$n _{ NH _4 Cl }= n _{ NH _4^{+}}=0.1+0.02=0.12$

$pOH = pK _{ b }+\log \frac{\left[ NH _4^{+}\right]}{\left[ NH _3\right]}$

$=4.745+\log \frac{0.12}{0.08}$

$=4.745+\log \frac{3}{2}$

$=4.745+0.477-0.301$

$pOH =4.921$

$pH =14- pH$

$=9.079$

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