Question
A load of $100\ kg$ is pulled up by $5m.$ Calculate the work done. $(8 = 9.8m/s)$

Answer

$\text { Mass }=100 \mathrm{~kg}$
$\text { Height }=5 \mathrm{~m}$
$\mathrm{~g}=9.8 \mathrm{~m} / \mathrm{s}^2$
$\text { P.E. }=\mathrm{m} \times \mathrm{g} \times \mathrm{h}$
$=100 \times 5 \times 9.8=4900 \mathrm{~J}$
Work done is equal to $PE$ acquired by the body.

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