A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of vessel is $5\,cm$ and its rotational speed is $2$ rotations per second, then the difference in the heights between the centre and the sides, in $cm,$ will be
JEE MAIN 2019Medium
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$y = \frac{{{w^2}{x^2}}}{{2g}} = \frac{{{{\left( {2 \times 2\pi } \right)}^2} \times {{\left( {0.05} \right)}^2}}}{{2g}}$
$ = 25 \times 8 \times {10^{ - 4}}$
$ = 2\,cm\,\,\,\,$
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