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Sound — Physics STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 SciencePhysicsSound3 Marks
Question
A man standing between $2$ parallel eliffs fires a gun. He hearns two echos one after $3$ seconds and other after $5$ seconds. The separation between the two cliffs is $1360\ m,$ what is the speed of sound?
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Answer

distance $(s) = 1360\ m,$
time for first echo $= 3\ s,$
time for second echo $= 5\ s$
To Find : speed of sound $(v)$
Formula : speed $=\frac{\text { distence }}{\text { time }}$
Calculation:
Time for first echo $= 3\ s$
$\therefore$ time taken by sound to travel given distance $t_1$
$=\frac{3}{2}=1.5 s$
Time for second echo $=5 s$
$\therefore$ time taken by sound to travel given distance $t_2$
$=\frac{5}{2}=2.5 s$
$\therefore$ Total time taken by sound to travel given distance, $T =1.5+2.5=4 s$
From formula,
$v=\frac{1360}{4} $
$\therefore v=340 m / s$

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