MCQ
A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is –
  • $\frac{L}{4}$
  • B
    $\frac{L}{2}$
  • C
    L
  • D
    $2 L$

Answer

Correct option: A.
$\frac{L}{4}$
$\frac{L}{4}$ We know that angular momentum $L = Mr ^2$
Here, $m$ and co are constants $L\ \\ \alpha\ \\ r^2$ If $r$ becomes $\frac{r}{2}$ angular momentum becomes $\frac{1}{4}$ th of its initial value.

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