$A$ metal rod of length $2$$m$ has cross sectional areas $2A$ and $A$ as shown in figure. The ends are maintained at temperatures $100°C$ and $70°C$ . The temperature at middle point $C$ is...... $^oC$
A$80$
B$85$
C$90$
D$95$
Medium
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C$90$
c (c) Let $\theta$ be temperature middle point $C$ and in series rate of heat flow is same
==> $K(2A)(100 - \theta ) = KA(\theta - 70)$
==> $200 - 2\theta = \theta - 70$
==> $3\theta = 270$==> $\theta = 90^\circ C$
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