Question
A metal $X$ forms a salt $XSO_4.$ The salt $XSO_4$ forms a clear solution in water which reacts with sodium hydroxide solution to form a blue precipitate $Y$. Metal $X$ is used in making electric wire and alloys like brass.
  1. What do you think metal $X$ could be$?$
  2. Write the name, formula and colour of salt $XSO_4.$
  3. What is the blue precipitate $Y?$
  4. Write a chemical equation of the reaction which takes place when salt $XSO_4$ reacts with sodium hydroxide solution. Give the state symbols of all the reactants and products which occur in the above equation.

Answer

  1. Metal $X$ could be copper $(Cu).$
  2. The salt $XSO_4$ is copper sulphate its formula is $CuSO_4$ and it is blue in colour.
  3. Copper hydroxide $[Cu(OH)_2]$ is the blue precipitate.
  4. $\text{CuSO}_4(\text{aq})\ +\ 2\text{NaOH(aq)}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{Cu(OH)}_2(\text{s})\ +\ \text{Na}_2\text{SO}_4(\text{aq})$

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