MCQ
$A [M(H_2O)_6]^{2+}$ complex typically absorbs at around $600\, nm$. It is allowed to react with ammonia to form a new complex $[M(NH_3)_6]^{2+}$ that should have absorption at ....... $nm$
- ✓$800$
- B$580$
- C$620$
- D$320 $
✓
Answer
Correct option: A.
$800$
a
As $NH_3$ is stronger ligand than $H_2O$, hence $CFSE$ value for $[M(NH_3)_6]^{2+} > CFSE$ of $[M(H_2O)_6]^{2+}$ therefore, absorption shifts to smaller wavelength. Also difference between splitting power of $NH_3$ and $H_2O$ is not very high.
As $NH_3$ is stronger ligand than $H_2O$, hence $CFSE$ value for $[M(NH_3)_6]^{2+} > CFSE$ of $[M(H_2O)_6]^{2+}$ therefore, absorption shifts to smaller wavelength. Also difference between splitting power of $NH_3$ and $H_2O$ is not very high.
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