MCQ
A molecule $M$ associates in a given solvent according to the equation $M\, \rightleftharpoons \,{(M)_n}$ For a certain concentration of $M,$ the van't Hoff factor was found to be $0 .9$ and the fraction of associated molecules was $0.2.$ The value of $n$ is
  • $3$
  • B
    $5$
  • C
    $2$
  • D
    $4$

Answer

Correct option: A.
$3$
a
$\Delta T_{b}=i . K_{b} \cdot m$

$C u C l_{2} \quad \rightarrow C u^{2+} \quad+2 C l$

$1 \quad 0 \quad 0$

$(1-\alpha)$

$2 \alpha$

$i=1+2 \alpha$

Assuming $100\, \%$ ionization So, $i=3$

$\Delta T_{b}=3 \times 0.52 \times 0.1=0.156 \approx 0.16$

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