MCQ
A molecule $M$ associates in a given solvent according to the equation $M$ $\rightleftharpoons $ $(M)_n$. For a certain concentration of $M$, the van't Hoff factor was found to be $0.9$ and the fraction of associated molecules was $0.2$. The value of n is
  • A
    $2$
  • $4$
  • C
    $5$
  • D
    $3$

Answer

Correct option: B.
$4$
b
$\mathrm{i}=\frac{\pi}{\mathrm{CRT}}$ $=\frac{16.42 \times 111 \times 100}{4.44 \times 1000 \times 0.082 \times 300}$ $=1.66$

$\mathrm{CaCl}_{2} \longrightarrow \mathrm{Ca}^{+2}+2 \mathrm{Cl}^{-}$

$\mathrm{i}=1+(\mathrm{n}-1) \mathrm{a}$

$1.66=1+(3-1) a$

$2 a=0.66$

$a=0.33$

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