- AElectrons will flow through external circuit in reverse direction.
- BThe opposite half cell reaction will take place spontaneously.
- CThe given reaction will not be spontaneous
- ✓All of the above
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$(i)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}OH}}$ $ (CH_3)_2CH - CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}O^-}} $ $(CH_3)_2CH - CH_2OC_2H_5 + Br^-$
The mechanisms of reactions $(i)$ and $(ii)$ are respectively
The above reaction is carried out in a vessel starting with partial pressure $\mathrm{P}_{\mathrm{SO}_{2}}=250\, \mathrm{~m}$ $bar,$ $\mathrm{P}_{0_{2}}=750 \,\mathrm{~m}$ $bar$ and $\mathrm{P}_{\mathrm{SO}_{3}}=0 \,\mathrm{bar}$. When the reaction is complete, the total pressure in the reaction vessel is $.....\mathrm{m}$ $bar.$ (Round off to the Nearest Integer).
$CoCl _{3} . xNH _{3}+ AgNO _{3}( aq ) \rightarrow$
If two equivalents of $AgCl$ precipitate out, then the value of $x$ will be $....$