Download App

STD 12 - 2. Electrochemistry — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 - 2. Electrochemistry4 Marks
MCQ
A negative $e.m.f.$ for a cell represents
  • A
    Electrons will flow through external circuit in reverse direction.
  • B
    The opposite half cell reaction will take place spontaneously.
  • C
    The given reaction will not be spontaneous
  • ✓
    All of the above
✓

Answer

Correct option: D.
All of the above
d
$EMF$ of the cell is always the difference in higher reduction potential and lower reduction potential. If the $EMF$ is negative, it indicates that the electron flow is in the reverse direction, both the reactions are not as spontaneous as they should be.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Alkene $R - C - H = C{H_2}$ reacts readily with ${B_2}{H_{6}}$ and the product on oxidation with alkaline hydrogen peroxides produces
→
The alkyl cyanides are
→
The most electropositive element possesses the electronic configuration
→
Amongst $CuF_2, CuCl_2$ and $CuBr_2$
→
The ionization energy of nitrogen is larger than that of oxygen because of
→
The major product of the following reaction is

$C{H_3} - CH = C{H_2} + HBr\xrightarrow{{{{({C_6}{H_5}CO)}_2}{O_2}}}$

→
Which of the following carbocation is most stable
→
Calculate the $\lambda$ of $CO_2$ molecule moving with a velocity $440\, m/s.$
→
The decreasing order of reactivity of $m-$ nitrobromobenzene $(I), 2, 4, 6-$ trinitrobromo-benzene $(II), p-$ nitrobromobenzene $(III)$, and $2,4-$ dinitrobromobenzene $(IV),$ towards $OH^-$ ions is
→
Given below are two statements: one is labelled as Assertion $(A)$ : and the other is labelled as Reason $(R)$. Assertion $(A)$ : Both rhombic and monoclinic sulphur exist as $S_5$ while oxygen exists as $O_2$.

Reason $(R)$ : Oxygen forms $\mathrm{p} \pi-\mathrm{p} \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $\mathrm{C}, \mathrm{N}$, which is not possible for sulphur.

In the light of the above statements, choose the most appropriate answer from the options given below :

→