MCQ
A neutral atom will have the lowest ionization potential when its electronic configuration is
- A$1{s^1}$
- B$1{s^2},\,2{s^2}{p^6}$
- C$1{s^2},\,2{s^2}{p^2}$
- ✓$1{s^2},\,2{s^2}{p^6},\,3{s^1}$
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Assertion $A$ : The first ionization enthalpy for oxygen is lower than that of nitrogen.
Reason $R$ : The four electrons in $2 p$ orbitals of oxygen experience more electron-electron repulsion.
In the light of the above statements, choose the correct answer from the options given below.
$Cu ( s )+2 Ag ^{+}( aq ) \rightleftharpoons Cu ^{2+}( aq )+2 Ag ( s )$
The equilibrium constant for the reaction.$\frac{1}{2} Cu ^{2+}( aq )+ Ag ( s ) \rightleftharpoons \frac{1}{2} Cu ( s )+ Ag ^{+}( aq )$ is $x \times 10^{-8}$. The value of $x$ is (Nearest Integer)
