MCQ
A neutral atom will have the lowest ionization potential when its electronic configuration is
- A$1{s^1}$
- B$1{s^2},\,2{s^2}{p^6}$
- C$1{s^2},\,2{s^2}{p^2}$
- ✓$1{s^2},\,2{s^2}{p^6},\,3{s^1}$
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$C{H_3} - CH(C{H_3}) - C{(C{H_3})_2} - C{H_2} - CH(C{H_3}) - C{H_2} - C{H_3}$
|
|
Primary |
Secondary |
Tertiary |
Quaternary |
|
$(a)$ |
$6$ |
$2$ |
$2$ |
$1$ |
|
$(b)$ |
$2$ |
$6$ |
$3$ |
$0$ |
|
$(c)$ |
$2$ |
$4$ |
$3$ |
$2$ |
|
$(d)$ |
$2$ |
$2$ |
$4$ |
$3$ |
$I . C H_{3}^{+}$ $II.$ $H_{3} O ^{+}$ $III.$ $N H_{3}$ $I V\,\, C H_{3}^{-}$