MCQ
A non-zero polynomial with real coefficients has the property that $f''(x) f'(x) = f(x)$ . Then the value of $f'''(x)$ is
- ✓$0$
- B$-1$
- C$f(x)$
- D$f'(x)$
Degree of $f^{\prime}(x)=n-1$
degree of $f^{\prime \prime}(x)=n-2$
$\therefore f^{\prime \prime}(x) f^{\prime}(x)=f(x)$
Then $(n-2)+(n-1)=n$
${2 n-3=n} $
${n=3}$
Now let $f(x)=a x^{3}+b x^{2}+c x+d$
Then $f^{\prime \prime \prime}(x)=0$
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