MCQ
A nucleus $_n{X^m}$emits one $\alpha $ and one $\beta $ particles. The resulting nucleus is
- A$_n{X^{m - 4}}$
- B$_{n - 2}{Y^{m - 4}}$
- C$_{n - 4}{Z^{m - 4}}$
- ✓$_{n - 1}{Z^{m - 4}}$
✓
Answer
Correct option: D.
$_{n - 1}{Z^{m - 4}}$
d
(d)$_{n}{{X}^{m}}{{\xrightarrow{\alpha }}_{n-2}}{{X}^{m-4}}{{\xrightarrow{-\beta }}_{n-1}}{{X}^{m-4}}$
(d)$_{n}{{X}^{m}}{{\xrightarrow{\alpha }}_{n-2}}{{X}^{m-4}}{{\xrightarrow{-\beta }}_{n-1}}{{X}^{m-4}}$
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