Question
A number when increased by $23\%$ becomes $861$; find the number.

Answer

Let the number be $x$ By the given condition,
$x+\frac{x \times 23}{100}=861$
$ \Rightarrow \frac{100 x+23 x}{100}=861$
$ \Rightarrow x\left(\frac{123}{100}\right)=861$
$ \Rightarrow x=\frac{861 \times 100}{123}=7 \times 100=700$
$\therefore$ the required number $=700$

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