MCQ
A pair of linear equations which has a unique solution $x = 2, y = -3$ is
  • $2x + 5y = -11, 4x + 10y = -22$
  • B
    $x - 4y -14 = 0, 5x - y + 13 = 0$
  • C
    $2x - y = 1, 3x + 2y = 0$
  • D
    $x + y = -1, 2x - 3y = –5$

Answer

Correct option: A.
$2x + 5y = -11, 4x + 10y = -22$
If $x = 2$ and $y = -3$ is a unique solution of any pair of equation, then these values must satisfy that pair of equations.
Putting the values in the equations for every option and checking it $-$
$\text{LHS} = 2x + 5y = 2 (2 + (-3) = 4 + (-15) = -11 = \text{RHS}$ and
$\text{LHS} = 4x + 10y = 4 (2) + 10 (-3) = 8 + (-30) = -22 = \text{RHS}$
It satisfies the pair of linear equation and hence is the unique solution for the equation.

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